Mathe Help.....10 points?

Question

Find equation of line which is perpendicular to x= -2 and goes through (3,-2)

Answer 1

***EDIT EDIT***

I made a mistake on my original answer. I did the negative reciprocal of x= -2 instead of the slope.

David S. is the first correct answer.

Recommend you give him the 10 points.

Also, I gave him a thumbs up.

Regards,

Mysstere

Answer 2

There are a few different ways of doing this question.

First, we know that the slope of a perpendicular line is a negative reciprocal to the original. I am assuming that when you say x = -2, you mean that the slope is negative 2, because I cannot think of what else you mean. So, anyways, the negative reciprocal of -2 is 1/2.

We then have a couple different methods for finding the equation of a line with the slope and point. Let's use the y = mx+b form.

In this form of equation, m = slope (1/2) and x and y are the points (3, -2). So, by substitution....

-2 = (1/2)(3) + b
-2 = 3/2 + b
b = -7/2

Since "b" represents the y-intercept, the equation of your perpendicular line is: y = (1/2)x - 7/2


Hope this helps!!!!

Answer 3

Find equation of line which is perpendicular to x= -2 and goes through (3,-2)

Ok. Well, this isn't too hard of a problem. The slope is going to be 0, because it has to be perpendicular to x = -2, and the slope of x=-2 is undefined.

First, write it out in point-slope form.

(y+2) = 0(x-3)

Simplify

y = -2

Cough... looking at other answers... cough... did I do that wrong? Looking back on the original question, I still stand by my answer.

Answer 4

x= -2 is perpendicular to y= -2