2007-03-05 13:12:17 · 5 answers · asked by Anonymous in Science & Mathematics ➔ Physics
V = d / t
1cm/s = 2000m/t
1cm/s * t = 2000m
1cm/s / 1cm/s * t = 2000m/1cm/s
t = 2000m/1cm/s
= 2000s
= 33.3min
= 0.55h
Therefore, it would take an object [2000s, or 33.3 min, or 0.55h] to fall 2000m.
2007-03-05 13:21:15 · answer #1 · answered by de4th 4 · 0⤊ 1⤋
I also get 55.55 hours
2000m x 100 cm/m = 200,000 cm.
at 1 cm/s, 200,000 cm = 200,000 s.
200,000s / 3600 s/hr = 55.555...hr.
Use the source Luke!
A good starting point what it is you need!
Follow the link below and you will find what you seek!
http://www.worldwidemetric.com/metcal.htm
2007-03-05 15:37:06 · answer #2 · answered by Anonymous · 0⤊ 0⤋
Arithmetic errors seem to have been common in your first 3 answsers. #2 forgot to convert between m & cm. #3 got the number of seconds in an hour wrong. Look their work over - you should be able to find their error and get my answer.
I get 55.55 hours
2007-03-05 14:22:58 · answer #3 · answered by sojsail 7 · 0⤊ 0⤋
2000m x 100 cm/m = 200,000 cm.
at 1 cm/s, 200,000 cm = 200,000 s.
200,000s / 360 s/hr = 555.55hr.
2007-03-05 14:00:39 · answer #4 · answered by STEVEN F 7 · 0⤊ 0⤋
5hours and 55 minutes
2007-03-05 13:15:47 · answer #5 · answered by sprousefan0013 1 · 0⤊ 0⤋