How many moles of CaF2 will dissolve in 3.0 liters of 0.050 M NaF solution? (Ksp for CaF2 = 4.0 x 10-11)
2007-03-05 12:28:54 · 3 answers · asked by jasmine m 1 in Science & Mathematics ➔ Chemistry
.. .. .. .. .. CaF2 <=> Ca+2 +2F-
Initial .. .. .. .. .. .. .. .. .. .. .. .. 0.05
Dissolve .. x
Produce .. .. .. .. .. .. .. x .. .. ..2x
At Equil .. .. .. .. .. .. .. ..x .. .. 0.05+2x
Ksp =[Ca+2][F-]^2 =x(0.05+2x)^2=
For simplicity let's assume that 0.05 >> x and 0.05 +2x=0.05
then Ksp=x*0.05^2 => x= (4.0*10^-11)/0.05^2 =1.6*10^-8 M
which means that our assumption is valid
You have 3L so mole CaF2 =M*V =1.6*10^-8 *3 = 4.8*10^-8
2007-03-05 21:50:42 · answer #1 · answered by bellerophon 6 · 2⤊ 0⤋
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2016-05-16 05:49:24 · answer #2 · answered by Anonymous · 0⤊ 0⤋
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