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Heres a crappy diagram of what the problem looks like:
<----[12kg]----[20kg]----[16kg...

Three boxes are tied together and are pulled forward on a frictionless surface by a rope with a tension of Ft=12N.

a) Write Newetons 2nd law equation for the horizontal forces on each box individually. (No numbers allowed)

b) Solve your three Newton's law equations for the acceleration of each box and the tension in each string. (Find numerical answers (with proper units.)

Any help? Im not sure what to do
Additional Details

41 minutes ago
The last box is 16kg since it cut the end of it off

2007-03-05 12:22:55 · 1 answers · asked by farxfromxlonelyx 1 in Science & Mathematics Physics

1 answers

Draw a free body diagram of each box with the positive direction in the direction of motion
T1, T2 are the tensions in the strings

Box 1

Ft-T1=m1*a
a is acceleration of each box since they are all connected on a frictionless surface

Box 2

T1-T2=m2*a

Box 3
T2=m3*a

T2=16*a
T2/16=a

Plug into #2
T1-T2=20*T2/16
T1=T2*(1+20/16)

Plug into #1
Ft-T2*(1+20/16)=12*(T2/16)
Ft=T2*(1+20/16+12/16)

T2=12*16/(16+20+12)
T2=4 N

T1=4*(1+20/16)

T1=9 N

j

2007-03-06 05:14:03 · answer #1 · answered by odu83 7 · 0 0

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