Near the surface of the earth, what is the accleration of an object due to the force of gravity?

Question

PLEASE HELP!! I 4got my science book at school, and this is due tomorrow

Answer 1

Near the surface of the Earth (not making any allowance for the resistance of air) acceleration due to gravity is 32 feet per second per second. In other words, the first second you, or something, falls 32 feet per second. The second second, you or it, is falling at 64 feet per second, then 96 feet per second, etc.
Terminal velocity is right around 160 miles per hour. After that
there is no further acceleration due to gravity.

The air in our atmosphere becomes more dense the closer you get to the surface of the Earth. Thus, various calculations need
to be made to determine what your final velocity will be, based upon the shape and air friction of the falling body or object. A
parachute or parafoil has little weight, but massive air resistance
and will therefore slow down a falling body in dense air. Parachutes have little effect in the thin atmosphere of high altitudes.

Answer 2

The acceleration of an merchandise loose-falling to the earth is continuously 9.80 one meters in line with 2d sqaured no count number number what. If the article isn't loose-falling a seperate formula could be used to bathe up for that acceleration. (Projectile action)

Answer 3

Acceleration is 32 feet per second, per second. The first second the speed reaches 32fps, the next second the speed is up to 64fps, then 96fps. This does not count atmospheric resistance.

Answer 4

32.2 feet per second

Answer 5

9.81 m/s^2