The pressure of 30. Ml of an ideal gas increases from 101 kPa to 202 kPa at constant temp...?

Question

the new volume is

1) 30. mL X 101 kPa/202 kPa

2) 30. mL X 202 kPa/101 kPa

3) 101 kPa/30. mL x 202 kPa

4) 202 kPa/30. mL x 101 kPa

Answer 1

Ideal gas law
PV = nRT

nRT is constant, so it cancels. This means you can set P1V1 = P2V2.

30 mL * 101 kPa = x * 202 kPa
30 mL * 101 kPa / 202 kPa = x
x = 15 mL

Answer 2

Boyle's regulation: P1V1=P2V2 50.sixty 5 kPa x 2 hundred mL=one hundred and one.3 kPa x V2 V2=(50.sixty 5*2 hundred)/one hundred and one.3=one hundred mL A) one hundred mL P.S. you've figured this out with out doing the mathematics. rigidity and volume are inversely proportional even as style of moles and temperature is held consistent so if the rigidity better the quantity had to shrink and the merely volume lower than the unique 2 hundred mL is A)one hundred mL.