The pressure of 30. Ml of an ideal gas increases from 101 kPa to 202 kPa at constant temp...?

Question

the new volume is

1) 30. mL X 101 kPa/202 kPa

2) 30. mL X 202 kPa/101 kPa

3) 101 kPa/30. mL x 202 kPa

4) 202 kPa/30. mL x 101 kPa

Answer 1

v1*p1=v2*p2

you know 3 of the numbers so lets plug em in

30*101=x*202
30*101/202=x

30*0.5=x
15=x