Forgot science book in my locker, please help! due tomorrow!!
2007-03-05 10:37:18 · 13 answers · asked by dramaqueen9261 1 in Science & Mathematics ➔ Astronomy & Space
g=9.8 m/s^2
2007-03-05 10:40:48 · answer #1 · answered by angel 3 · 0⤊ 0⤋
The acceleration of an object free-falling to the earth is always 9.81 meters per second sqaured no matter what. If the object is not free-falling a seperate formula must be used to solve for that acceleration. (Projectile Motion)
2007-03-05 10:46:19 · answer #2 · answered by Anonymous · 0⤊ 0⤋
a: ) The rigidity of gravity performing on an merchandise close to the Earth's floor is proportional to the mass of the article, F = G m1 m2 / r^2 taking m2 = mass of earth = consistent r = radius of earth + tiny bit = consistent for that reason F prop. to m1 QED b: ) yet a heavy merchandise does not fall swifter than a delicate merchandise because of fact the acceleration is self sustaining of the products mass. F = m1 a and F = G m1 m2 / r^2 m1 a = G m1 m2 / r^2 whence a = G m2 / r^2 and so self sustaining of m1 QED
2016-10-17 08:38:49 · answer #3 · answered by ? 4 · 0⤊ 0⤋
I remember from last year that it's 9.8 miles per second.
2007-03-05 10:42:35 · answer #4 · answered by Anonymous · 0⤊ 0⤋
9.8 meters per second squared
2007-03-05 10:45:26 · answer #5 · answered by Lauren 4 · 0⤊ 0⤋
9.8 meters per second squared.
2007-03-05 10:41:32 · answer #6 · answered by lucielu 2 · 0⤊ 0⤋
It is 9.8 m/s^2.
2007-03-05 10:39:21 · answer #7 · answered by Mike 2 · 2⤊ 0⤋
basically, 9.81m/s^2 is accurate for most calculations(in high school physics).
2007-03-05 10:44:12 · answer #8 · answered by datz 2 · 0⤊ 0⤋
9.8 m/s^2
2007-03-05 10:40:01 · answer #9 · answered by Mr. Smith 5 · 0⤊ 0⤋
fg^25 = matter+distance.
2007-03-05 10:39:43 · answer #10 · answered by Phlow 7 · 0⤊ 1⤋