What is the tension of the cord in this image?
http://img255.imageshack.us/my.php?image...
Assume that the three blocks portrayed in Figure P4.27 move on a frictionless surface and that a F = 48 N force acts as shown on the m = 2.5 kg block.
I cant figure out how to get this...I got the acceleration of 8.727272 which is right. but I cant get the tension I take the acceleration add it to 9.8 and then multiply by the mass, I wasnt sure which mass to multiply it by to get the tension though because the problem has blocks on both ends, I think its just the blocks on the left right?
18.5272727272*3=55.58181818 N but the problem says its wrong...help?
2007-03-05 10:19:04 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Physics
I cannot access your image, so I cannot help you.
2007-03-05 10:28:17 · answer #1 · answered by msi_cord 7 · 0⤊ 0⤋
Sorry, I can see the picture to tell. But if that acceleration you found is correct, then all you need to do is solve for the tenison of the cord from the second law appilied to one of those blocks. I am of course assuming that the blocks are all attached or some way and that move as a whole with this acceleration you have given. The cord is ideal so I know so doesn't matter what equation you use unless it has more unkowns.
2007-03-05 18:33:13 · answer #2 · answered by Anonymous · 0⤊ 0⤋