a 34 kg box rests on the back of a truck. the coefficient of static friction between box and truck bed is .233. the acceleration of gravity is 9.8 m/s^2. also what is the max acceleration can the truck have before the box slides ?
2007-03-05 10:03:17 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Physics
OK...
f= a m =>
(f) is the maximum force that comes from the maximum acceleration of the truck.... f= a m as: a= truck acceleration......OK!
m= mass of box........ then the maximum acceleration that the truck can have before the box slides a= f\m.....right!
the maximum force that can be applied on the box without sliding equals F= (Cs) m g.........
then F=(233)(34)(9.8)=77635.6 N.........OK !
from this we can say f=F=77635.6=a(34)
==>>> a =2283.4 m\s^2
(the force that accelerates the box is the friction force )
2007-03-05 10:22:22 · answer #1 · answered by JwH 2 · 0⤊ 0⤋
James has the correct answer for the maximum acceleration. However he didn't mention what force casues the box to accelerate.
Supppose the box were on a frictionless surface. Then it would not accelerate and the truck would slid out from under the box as it accelerates. Thus it is the friction force that accelerates the box.
Bye Mike R
2007-03-05 18:23:52 · answer #2 · answered by MICHAEL R 2 · 0⤊ 0⤋
.233 * 9.8 = 2.28 m/s^2
2007-03-05 18:12:12 · answer #3 · answered by bruinfan 7 · 0⤊ 0⤋