Basically.. The experiment is to see how many drops of sodium hydroxide it takes to neutralize different concentrations of vinegar (ethanoic acid)....
Would it basically be that the the less concentrated the vinegar, the less drops of NaOH are needed to make the solution turn green (with universal indicator)?
And could anyone expand that a bit please?
(I'm in KS3)
Lorna
2007-03-05 06:09:07 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
yes - you have the basic idea, the more concentrated the vinegar, the more sodium hydroxide you will have to add
the reaction is
HC2H3O3 + NaOH --> H2O + NaC2H3O2
think of it as the H from the vinegar combining with the OH of the sodium hydroxide to make the water (H2O)
the more H you have (higher concentration of vinegar) the more OH you need to convert it to water
the green color indicates that all of the H has been converted into water
2007-03-05 06:30:10 · answer #1 · answered by chem geek 4 · 0⤊ 0⤋
Acetic acid is a weak acid, while sodium hydroxide is a strong base. Which only means that it takes fewer drops of NaOH to neutralize a given quantity of acetic acid.
The more concentrated the acetic acid, the more acidic it is, and rquires more NaOH to neutralize it.
As acids are more concentrated, the kH+ is higher (concentration of hydrogen ions) requiring more OH- ions (anions) to neutralize it.
2007-03-05 14:52:54 · answer #2 · answered by Matthew P 4 · 0⤊ 0⤋
http://www.chemistry-react.org/go/Tutorial/Tutorial_4948.html this website may help
2007-03-05 14:16:15 · answer #3 · answered by Anonymous · 0⤊ 0⤋
A bitter tongue?
2007-03-05 14:11:52 · answer #4 · answered by Yea Yea 4 · 0⤊ 1⤋