A 0.220 kg metal rod carrying a current of 10.0 A glides on two horizontal rails 0.520 m apart. What vertical magnetic field is required to keep the rod moving at a constant speed if the coefficient of kinetic friction between the rod and rails is 0.100?
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2007-03-05 05:27:24 · 1 answers · asked by Anonymous in Science & Mathematics ➔ Physics
Rod will move with constant speed if Lorentz magnetic force
is balanced by kinetic friction.
Magnetic field Bx current Ix length of rod =
co eff of frictionxweight of rod
Bx10x0.520=0.100xo.220x9.8
B =22x0.098/52
=0.041 tesla
2007-03-05 06:29:38 · answer #1 · answered by ukmudgal 6 · 0⤊ 0⤋