how do you proove that two triangles are similar if they are bidsecting eachother at the top so theyre like facing eachother? i have been given three measurements if this helps
2007-03-05 05:26:15 · 5 answers · asked by jenny 1 in Science & Mathematics ➔ Mathematics
I'm not sure what the picture looks like. But, to prove two triangles similar you need to prove that two angles of one are congruent to two angles of the other. Look for things like vertical angles and corresponding angles associated with parallel lines.
2007-03-05 05:42:38 · answer #1 · answered by PKM 2 · 0⤊ 0⤋
I do not know whether this helps but two triangles are congruent (similar) if they have 3 same sides or 3 same angles so try and use the sine rule or cosine rule or whatever to find a way to get 3 equal sides/3 equal angles
2007-03-05 13:52:57 · answer #2 · answered by billymysterio 2 · 0⤊ 0⤋
Your question is unclear because it is difficult to know what you mean by bisecting each other. You say you have three measurements. Are they angles or sides or both?
To prove two triangles are similar, you need to prove that two angles of on are equal to two angles of the other.
Or, you have to show that the sides are proportional.
Resubmit your question with a better description and you will get an answer.
2007-03-05 13:47:54 · answer #3 · answered by ironduke8159 7 · 0⤊ 0⤋
well, I think that wih that few information you will not answer that.
You have to measure their lengths and then compare them. Each segment of the triangle is like a vector, then using Pitagoras you will obtain their lengths and compare them.
2007-03-05 13:38:44 · answer #4 · answered by Garcia J 1 · 0⤊ 0⤋
Similar Triangles have the same shape but not the same size.
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2007-03-05 15:31:05 · answer #5 · answered by SAMUEL D 7 · 0⤊ 0⤋