appropiate degree of accuracy?

Question

here is the lower and upper bound for a volume

51561.25cm^3
45581.25cm^3

write down the volume in cm^3 to an appropriate degree of accuracy

Answer 1

This can be written as:

48,571.25cm^3 +/- 2990cm^3

2990 is 1/2 the difference (or range)

Answer 2

51561 - 45581 = range
Volume = range/2 +lower bound
= 5980/2 + 45581
= 2990 + 45581
=48571cm^3

=48571 + or - 2990 cm^3 or

48571cm^3 + or - 4.714 percent