Okay... I have 30 "questions", and 6 people to match up to those questions. They each match up to 5, obviously. Is there any way for me to find out the different combinations to these??
For reference - 30 questions, 6 people, who I will call - L, T, H, A, O, and K.
2007-03-05 05:03:59 · 3 answers · asked by It'sJustMe 2 in Education & Reference ➔ Homework Help
There are ONLY 5 questions for each person - there is no replication.
2007-03-05 05:10:48 · update #1
I guess I should have used different wording. They are more like statements than question. There are ONLY 5 statements that apply to each person - there is no replication.
2007-03-05 05:16:48 · update #2
Going by what you said, there are 6!(30!) possible combinations for this...that's almost 2.5x10^36 answers. So to answer your question: yes, but not easily. =P
2007-03-05 05:18:09 · answer #1 · answered by Anonymous · 0⤊ 0⤋
You assume they "obviously each match up to 5"...why is that? Why can't people double up on one? Or one have 4 and some other have 6?
May be even more complicated than you thought right?
Math wise you would look at the number of possible combinations you can make with 30 questions into 6 sets of 5. THAN you can switch those options around among the 6 ...
Be care full not to do the ! it also includes switching the order of questions.... 12345 is the same as 15243 but counts as a new set when just doing a logarithm
...Boggles my mind.
2007-03-05 05:08:59 · answer #2 · answered by Puppy Zwolle 7 · 0⤊ 0⤋
Is it, like, the questions are divided into 6 different categories of 5 questions each, and each person has 5 questions, one from each category?
2007-03-05 05:08:39 · answer #3 · answered by Mark D 2 · 0⤊ 0⤋