just checking, in the lottey theres 29 different balls that can come, and 6 different balls chosen, how many different combinatons do you get, i get around, 475020 different variations, what you get?
2007-03-05 05:00:46 · 6 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
29!/(6!*23!)
(29*28*27*26*25*24)/(6*5*4*3*2*1)
475020 is correct.
2007-03-05 05:05:01 · answer #1 · answered by Dave 6 · 1⤊ 0⤋
Does the order in which the balls are drawn matter? If it does, then the answer would be 29*28*27*26*25*24 = about 342 million.
2007-03-05 05:08:00 · answer #2 · answered by PKM 2 · 0⤊ 0⤋
342,014,400 = 29*28*27*26+25*24
2007-03-05 05:06:49 · answer #3 · answered by ironduke8159 7 · 0⤊ 0⤋
Yes that is correct The answer is 29!/[(29-6)!(6)!] = 475020
2007-03-05 05:13:06 · answer #4 · answered by physicist 4 · 0⤊ 0⤋
29! / (6! * 23!)
2007-03-05 05:03:47 · answer #5 · answered by Meg W 5 · 1⤊ 0⤋
29C6 = 475020, that's correct.
2007-03-05 05:09:07 · answer #6 · answered by ag_iitkgp 7 · 0⤊ 0⤋