Can someone give me the basic word and symbol equation for vinegar (ethanoic acid) reacting with sodium hydroxide - I'm in KS3 so I don't want anything too complicated (with things cancelling eachother out etc).
Lorna
2007-03-05 04:50:36 · 9 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
Ethanoic acid + sodium hydroxide ----> sodium ethanoate + water
CH3COOH + NaOH -----> CH3COONa + H2O
You don't need to know this equation for KS3!
2007-03-05 04:54:47 · answer #1 · answered by Gervald F 7 · 6⤊ 0⤋
NaOH + HCl = NaCl + H2O This is the classic acid + alkali gives a salt + water. In Words, Sodium Hydroxide plus Hydrochloric Acid gives Sodium Chloride plus water.
2016-03-18 03:56:31 · answer #2 · answered by Allyson 2 · 0⤊ 1⤋
Ethanoic Acid + Sodium Hydroxide -> Sodium Ethanoate or Sodium Acetate + Water
CH3COOH + NaOH -> CH3COONa + H2O
2007-03-05 04:59:45 · answer #3 · answered by ag_iitkgp 7 · 0⤊ 0⤋
Ethanoic Acid + Sodium Hydroxide = Sodium Ethanoate + Water
CH3COOH + NaOH = CH3COONa + H2O
2007-03-05 04:57:42 · answer #4 · answered by E M 4 · 2⤊ 0⤋
Ethanoic acid + sodium hydroxide ----> sodium ethanoate + water
CH3COOH + NaOH -----> CH3COONa + H2O
2015-02-16 16:39:55 · answer #5 · answered by maheshwar 1 · 0⤊ 0⤋
Ethanoic Acid
2016-10-04 09:40:12 · answer #6 · answered by regula 4 · 0⤊ 0⤋
ethanoic acid + sodium hydroxide = sodium ethanoate + water
CH3COOH + NaOH = CH3COONa + H2O
(please excuse the numbers 3 & 2 above not being subscript as they should be, I can't persuade my computer to do subscripts yet, maybe I have to pay a subscription for this Ha-Ha!
2007-03-05 04:59:05 · answer #7 · answered by cornettofile 1 · 2⤊ 1⤋
CH3COOH + NaOH -------> CH3COONa + H2O
The above equation is simply the neutralization of a weak acid and a strong base which proceeds by the exchange of different charges. the H+ In CH3COOH and the OH- of NaOH simply reacts to give H2O while the remaining CH3COO- reacts with the Na+ to give CH3COONa.
2007-03-05 05:51:46 · answer #8 · answered by dessy 2 · 1⤊ 0⤋
good job gervald
2007-03-05 04:56:15 · answer #9 · answered by genius'n'training 2 · 1⤊ 0⤋