a man had x no.of apples which he could arrange in 3 or 5 or 7 or 9 in a row and everytime 1 apple would be remaning. and the same x no. of apples when arranged in11 in a row no apples would be remaining with him. what is the no. of apples the man has???
2007-03-05 04:50:20 · 2 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
946 apples.
If you divide the number of apples by 3, 5, 7 or 9 you always end up with 1.
x = 3*5*7*9 THIS number is divisible by 3, 5, 7, 9.
now sum 1:
x = 3*5*7*9 + 1
This will guarantee that you're always left with 1 when you divide by any of the numbers 3, 5, 7, 9. YOu get:
x = 3*5*7*9 + 1 = 946
Now let's see if this is in fact divisible by 11:
946/11 = 86 exactly
Done.
2007-03-05 04:55:26 · answer #1 · answered by Ferts 3 · 1⤊ 0⤋
Number of apples = 3*5*7*9 + 1 = 946
2007-03-05 05:28:35 · answer #2 · answered by ag_iitkgp 7 · 0⤊ 0⤋