2007-03-05 04:35:49 · 3 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
X³ + Y³ =0 is:
X³ + Y³ = (x + y)(x² – xy + y²)
while X³ - Y³=0 is:
X³ + Y³ = (x - y)(x² + xy + y²)
hope that i help you right...
2007-03-05 04:57:29 · answer #1 · answered by graze 3 · 1⤊ 0⤋
in case you have x/y = 0, then multiply the two components by ability of y to get carry of x = 0. it is not correct what y is as long as y isn't 0 itself. x/y = 0 isn't the comparable as x = y for extremely the comparable reason. x must be 0 interior the 1st equation, yet while x = y then y could be 0, and it is trouble-free to no longer divide by ability of 0. while you're utilising standard gadgets (and you ought to be - T must be in seconds and g must be in meters in line with 2d squared), then L will yield meters. carried out!
2016-12-14 11:24:18 · answer #2 · answered by Anonymous · 0⤊ 0⤋
x^3 + y^3 >> (x + y)(x^2 - xy + y^2)
x^3 - y^3 >> (x + y)(x^2 + xy + y^2)
2007-03-05 04:46:36 · answer #3 · answered by milamtil 2 · 1⤊ 0⤋