12.00 moles of 2NaClO3 will produce how many grams of O2?

Question

It's Stochiometry.

Answer 1

NaClO3 -> NaCl + 3/2 O2

12 moles of NaClO3 will give 18 moles of O2 or 18x32 g of O2 i.e. 576 g of O2.

Answer 2

We first right down the chemical equation which tells us how 2NaClO3 gets reduced to produce O2.

Equation:
2NaClO3 -> 2NaCl + 3O2

From this equation we see that 1 mole of 2NaClO3 will give 3 moles of O2.
Thus, 12 moles of NaClO3 will give 3*(12) moles of O2 i.e. 36 moles of O2.

1 mole of 02 weighs 32 grams.
Thus, 36 moles of 02 weighs 36*32g i.e. 1144 grams.

Hence, 12 moles of 2NaClO3 will produce 1144 grams of O2.