how do you find x by factorising:
(2x^2 + 9x +4) - x = 26
thank you
2007-03-05 03:59:31 · 3 answers · asked by me m 1 in Science & Mathematics ➔ Mathematics
thank you.. but why... could you do it step by step
thanx
2007-03-05 04:12:26 · update #1
what does it mean when it then says chose a suitable value for this question? ?
2007-03-05 04:22:59 · update #2
1) We start with:
(2x^2 + 9x + 4) - x = 26
2) First we combine like terms:
2x^2 + 8x +4 = 26
3) Then we move the 26 over by subtracting 26 from both sides:
2x^2 + 8x -22 = 0
4) Factor out the 2:
2(x^2 + 4x -11) = 0
5) Now divide both sides by 2:
x^2 + 4x - 11
At this point we see that we cannot factor. We need to either use the completing the square method or the quadratic formula.
The answer will be 2 + sqrt(15) or 2 - sqrt(15)
2007-03-05 04:16:05 · answer #1 · answered by math_prof 5 · 1⤊ 0⤋
2x^2+8x+x+4 - x = 26
or 2x(x+4)+1(x+4) - x = 26
or (2x+1)(x+4) - x = 26
It is a real number.
2007-03-05 12:11:46 · answer #2 · answered by ag_iitkgp 7 · 1⤊ 0⤋
x=-square root of 15 - 2
x=square root of 15 - 2
2007-03-05 12:08:18 · answer #3 · answered by Anthony 2 · 1⤊ 0⤋