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straight line passes through points (0,5) and (3,17)

find the equation of the straight line?

2007-03-05 03:30:08 · 9 answers · asked by Twista-Adzy 2 in Science & Mathematics Mathematics

10 points go to the first answer if it is good and relevant

2007-03-05 03:34:22 · update #1

9 answers

i love these!
gradient (m) = y2 - y1 / x2 -x1
gradient = 17-5 / 3-0
gradient = 12/3 = 4

y = mx + c (take it at (0,5))
5 = 4 x 0 +c
5=0+c
c=5

y=mx+c
y=4x+5

hope that helps

2007-03-05 03:35:10 · answer #1 · answered by KaZ 2 · 1 0

Your answer will have several steps.

First, you need to determine the gradient or slope of the line. For this you use:

m = (y2 - y)/(x2 - x1)

Note that the 1 and 2 should be written as subscripts.

The two points give you the values of x1, x2, y1 and y2. Note it does not mater which way round you pick them. So let;
x1 = 0, y1 = 5 and x2 = 3, y2 = 17

That gives: m = (17 -5)/(3 - 0)
m = 12/3
m = 4

Now use: m ( x - x1) = y - y1. So you have;
4 ( x - 0) = y - 5
4x = y - 5
y = 4x + 5

Which is in the form of the general equation of a straight line
y = mx +c.

c = 5 and is the intercept of the line on the y axis.

For top marks, always check your equation using the second point. Here x = 3 and y = 17. So you have:

17 = 4*3 + 5
17 = 12 + 5
17 = 17 as expected.

2007-03-05 04:56:25 · answer #2 · answered by Anonymous · 0 0

Find the slope of the line first,
17-5/3-0=4
Now that you know the slope of the line, you can use the slope intercept form of line equation, which is
y=mx+b, where m is the slope and b is the y intercept.You can use any of the two points given, and for this case (0,5)
And finally you would get,
y=4x+5.

2007-03-05 03:43:22 · answer #3 · answered by a43cha 2 · 0 0

First determine the slope: (-11 - -3) / (-4 - 0) = 2 Second, use general line equation: (a = slope) (y - y0) = a * (x - x0), where (x0, y0) is any point on the line for(0, -3) y - -3 = 2 * (x - 0) y + 3 = 2x y = 2x - 3 for(-4,-11) y - - 11 = 2 * (x - - 4) y + 11 = 2x + 8 y + 3 = 2x y = 2x - 3 See, they result in the same equation :-)

2016-03-29 00:50:56 · answer #4 · answered by Anonymous · 0 0

from the given points:
y2-y1 = 17-5 =12
x2-x1= 3-0=3
the y-intercept is 5 ( from the data point (0,5))
so the equation for the line is:
y=(12/3)x +5
y = 4x+5

2007-03-05 03:37:30 · answer #5 · answered by jaybee 4 · 0 0

Gradient, m = (17 - 5 ) / (3 - 0) = 12 / 3 = 4
Line passes thro` (0 , 5): -
y - 5 = 4.(x - 0)
y = 4 x + 5 is equation of line.

2007-03-05 03:41:28 · answer #6 · answered by Como 7 · 0 0

y = 4x + 5

2007-03-05 03:35:36 · answer #7 · answered by Doug 5 · 1 0

y=4x+5

2007-03-05 04:44:41 · answer #8 · answered by omo 2 · 1 0

(y-y1)/(x-x1)=(y1-y2)/(x1-x2), where

x1=0
y1=5

x2=3
y2=17

Ans: 4x-y+5=0

2007-03-05 03:39:01 · answer #9 · answered by quest 2 · 0 0

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