The lattice energy of CsI(s) is −604 KJ/mol, and the enthalpy of solution is 33 KJ/mol. Calculate the enthalpy of hydration (KJ) of 0.750 moles of CsI.
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2007-03-05 03:15:22 · 4 answers · asked by Foxychick 1 in Science & Mathematics ➔ Chemistry
-428.25 kJ
2007-03-05 03:31:41 · answer #1 · answered by Dr Dave P 7 · 0⤊ 0⤋
The person above me has the correct answer, but the first person to respond to this is incorrect. First: The equation of Enthalpy of solution is H(sol)= - (lattice energy)+H(hydration) H=enthalpy So, substitute all of your numbers: H(sol)= - ( -715 ) + ( - 684) H(sol)=31 kJ/mol Then multiply this number by the number of moles: 31 kJ/mol x 1.23 = 38.13 kJ/mol
2016-03-29 00:50:14 · answer #2 · answered by Anonymous · 0⤊ 0⤋
.75(-604+33)
2007-03-05 04:00:23 · answer #3 · answered by ag_iitkgp 7 · 0⤊ 0⤋
http://magegame.ru/?rf=cbfee1eee2ede8f6e05fd1ece5f0f2e8
2007-03-05 03:22:33 · answer #4 · answered by Tatjana M 1 · 0⤊ 0⤋