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details please

2007-03-05 03:12:14 · 4 answers · asked by Jake 1 in Science & Mathematics Mathematics

4 answers

Ok, here you need to use substitution :

integrate(dx / x*sqrt(lnx))

sqrt(lnx) = (lnx)^-1/2

well, let`s use the substitution : lnx = t

in other words, e^t= x

then dx = e^t*dt

Now when we use the substitutions :

integrate( e^t*dt / e^t*t^-1/2)

integrate( dt / t^-1/2)

this will result = 2*t^1/2

t = lnx, then the final result will be : 2*lnx^1/2

2007-03-05 03:23:14 · answer #1 · answered by anakin_louix 6 · 0 0

Let z= ln x

So it becomes dz/sqrt(z)

The integral is 2 sqrt(ln x) + c

2007-03-05 03:25:00 · answer #2 · answered by ag_iitkgp 7 · 0 0

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2016-12-14 11:21:32 · answer #3 · answered by Anonymous · 0 0

i know only differentiation

2007-03-05 03:25:08 · answer #4 · answered by ram kumar 2 · 0 0

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