What are all the forces acting on this box?

Question

A box of mass 12 kg sits on a level surface. The coefficient of friction between the box and the floor is 0.25. A rope attached to the box pulls it horizontally to the right with a force of 38N. What are all the forces acting on the box?

How do you think the magnitude of the normal force on the box compares to the weight of the box? Is this a Newton's third law force pair?

Answer 1

Ok, here we need to make a graphic. You draw the box and the force of 38 N.

Then you know that the box has a weight og 12g Newtons

Let's consider g = 9.8 m/s^2

then the weight will be = 117.6 N

Using the third law of force, there is a Normal force on the box, that has the same value of the weight : 117.6 N

Normal force = 117.6 Newtons >>> Newton's third law force pair.

Now, there is friction, so using the normal force, we can draw the friction that is going against the direction of the force of 38 N.

Force of friction = 117.6*0.25 = 29.4 N

Then you will have :

The force of 38 N

The weight = 117.6 N

The Normal force = 117.6 N

The force of friction = 29.4 N

Answer 2

F(gravity), F(normal), F(pull), F(friction)

F(normal)=F(gravity)

yes