geometric sequence question, HELP?

Question

In the equation for the nth term of a geometric sequence tn = a(r)^n-1, the variable that represents the first term is:

a) a
b) r
c) n
d) tn

Answer 1

First term is 'a'. Second term is ar. 3rd=a^2, 4th-a^3.....

Here you will notive that For any term,
tn=a(r)^(n-1) as indicated by you. So a is the first term. Then another value r will be multipled in every next term.
Eg:
if a=3
r=2
Sequence is 3, 3*2, 3*2*2, 3*2*2*2,.....
0r 3, 6, 12, 24,.....

This is very similar to Arithematic Progression. The difference is there you will add a term d, instead of multiplying

Answer 2

First term is tn for n = 1 and so it is a!
Correct answer is a)

Answer 3

you are able to desire to discover the ratio r first. 3750/a hundred and fifty = 25 5th term - third term = 2 so sqrt(25) = 5 r=5 then you prefer a1 for that reason you are able to in simple terms paintings backward by dividing by 5 two times and get a1=6 or you need to use the the a(n) formula a(n) = a1( r^(n-a million) ) if n=3 then a hundred and fifty = a1 ( 5^2) a1=6. a9= a1 ( r^8) a9 = 6 (5^8) a9= 2343750

Answer 4

a since r^0 =1 so ar^0=a