English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

I got a question that is surprisingly simple but for some reason I just can't figure it out. Its beyound me, I don't know why, can anybody help me?

The problem is: (fog)(x):
g(x) = 3/(x - 1), f(x) = (x - 1)/(x - 3)

2007-03-05 01:17:18 · 2 answers · asked by Remnant 2 in Science & Mathematics Mathematics

Yes (fog)(x) would be f(g(x))

2007-03-05 01:27:48 · update #1

2 answers

g(x) = 3 / (x-1)
f(g(x)) = [3/(x-1) - 1] / [3/(x-1) - 3] = (3 - x + 1)/ (3 - 3x +3)
= (4 - x) / (6 - 3x)

2007-03-05 03:42:49 · answer #1 · answered by FedUp 3 · 0 0

do you mean f(g(x))?
if that is the case, then
f(g(x))= (3/(x-1)-1)/(3/(x-1)-3)
it is just plugging the function in another function.
to make it more clear, use f(x)=x^2 and g(x)=3x for example
f(g(x))=f(3x)=(3x)^2
g(f(x))=g(x^2)=3x^2

2007-03-05 09:22:53 · answer #2 · answered by Jim Chen 2 · 0 0

fedest.com, questions and answers