Findo two numbers whose difference is 100 and whos product is a minimum.
I don't know if my equation is right so if you all could take a shot at it that would help! Teacher doesn't go very in depth on some aspects of our homework! Sorry!
2007-03-04 22:39:46 · 6 answers · asked by Linz 2 in Science & Mathematics ➔ Mathematics
There's an equation taht has to be used useing derivatives...not quite sure how to set this one up.
2007-03-04 22:44:48 · update #1
x*(x-100) should be minimum
=> x^2 -100x should be minimum
diff w.r.t.x and equate to 0.
2x - 100 = 0
=> x = 50 and the other number is -50.
thus the minimum product is -2500 and not 0 as mentioned previously.
2007-03-04 22:46:14 · answer #1 · answered by FedUp 3 · 3⤊ 0⤋
x - y = 100, so y = x - 100
the product is x*y = x*(x-100) = x^2 -100x
since you have an expression, take the derivative and let it equal zero:
2x - 100 = 0
so x = 50 and y = -50
2007-03-04 23:15:42 · answer #2 · answered by Biznachos 4 · 3⤊ 0⤋
101 and 1
2007-03-04 22:42:48 · answer #3 · answered by Yankee Killer 2 · 0⤊ 5⤋
the answers are 99 and -1
or
101 and 1
100 and 0 is also possible
2007-03-04 22:49:02 · answer #4 · answered by slimshady 1 · 0⤊ 3⤋
0 and 100
difference is 100
product is zero - can't get more minimum than that!
2007-03-04 22:44:29 · answer #5 · answered by tomkat1528 5 · 0⤊ 4⤋
100and 0arethe two numbers
2007-03-04 22:44:12 · answer #6 · answered by varun hi 1 · 0⤊ 4⤋