2007-03-04 20:43:40 · 11 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
i=under root(-1)
2007-03-05 00:04:35 · answer #1 · answered by Anonymous · 0⤊ 0⤋
i =square root of (-1). That's its value. Clearly,that's quiet abstract to imagine but that's what it is. It is an imaginary number and you cannot expect a real value ( as in the case of e=2.718 or pi=3.142) for it.
2007-03-04 21:07:20 · answer #2 · answered by Anonymous · 0⤊ 0⤋
i, the square root of -1, is an artificial number, used for creating a new field named Z - the complex numbers. Z is a generalization of R. Surprizingly some theorems that applies for the real numbers apply for the complex numbers as well, and the theory of complex numbers helps to solve problems in field R.
2007-03-04 21:06:06 · answer #3 · answered by Amit Y 5 · 0⤊ 0⤋
"i" is defined as the square root of -1. It has no real value, meaning that it has no place on the real number line.
2007-03-04 22:11:42 · answer #4 · answered by Anonymous · 0⤊ 0⤋
The value of i is square root of -1.
You generally use it in summation and algebric problems.But you dont need to substitute its value.It is kept as i only.
2007-03-04 20:55:36 · answer #5 · answered by Z....... 2 · 0⤊ 0⤋
It is square root of -1.
2007-03-04 22:03:35 · answer #6 · answered by You-Know-Who 2 · 0⤊ 0⤋
'i' is an imaginary number. It cannot be shown as a real number. Its value is square root of minus one.
2007-03-04 20:51:54 · answer #7 · answered by Ravi 2 · 0⤊ 0⤋
i may be the square root of -1, so that's it's value.
2007-03-04 20:47:56 · answer #8 · answered by JJ 7 · 1⤊ 0⤋
i=a umber that if you calculate
i^2 you will find -1!
i its an imaginary number!
2007-03-04 20:48:19 · answer #9 · answered by Anonymous · 2⤊ 0⤋
i=(-1)^1/2
it can not be expressed as a real number
2007-03-04 20:48:47 · answer #10 · answered by Anonymous · 0⤊ 0⤋