Books are not always right.
Answer is none other than -8
f(-1)=2(-1)^2+4(-1)-6
f(-1)=2(1)-4-6
f(-1)=2-4-6
f(-1)=-8
thats the final answer and im 300% sure
2007-03-04 22:07:37
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answer #1
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answered by Ali 3
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Substitute x = -1 into the formula.
f(x)=2x^2+4x-6
=2(-1)^2+4(-1)-6
=2-4 -6
=-8
f(x) =-8
If I am not mistaken, -1 is not a factor.
2x^2+4x-6
x^2+2x-3
(x+3)(x-1)
x = 1 is a factor.
or
x = -3
I don't think that the value x = -1, but I may be wrong. Also, I don't know how to maker --16
+16.
Dexter T
2007-03-08 18:12:12
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answer #2
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answered by Anonymous
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The question should say 'Evaluate f(x) = .... when x = -1', or 'Solve f(x) = 0 where f(x) = 2x^2 + 4x + 6'. Then it would make sense. Is this an Edexcel question?
2007-03-04 20:58:42
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answer #3
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answered by Anonymous
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I don't know about -16. From your equation, I'd say:
2x^2 = 2
4x = -4
-6 = -6
add them together:
2 - 4 - 6 = -8,
unless there's something we're both missing!
2007-03-04 20:52:59
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answer #4
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answered by JJ 7
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If x=-1
Then Then put -1 wherever there is x,
f(-1)=2(-1)^2+4(-1)-6
=2(1)-4-6 [as(-1)^2 = 1]
=2-10=-8
2007-03-04 21:51:29
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answer #5
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answered by Anonymous
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are you sure that is what the book says? -16?
its not a factoring problem, you just sub -1 for x and solve like normal
f(x) is just a fancy way of saying y
so read y = 2(-1)^2...
2007-03-04 20:55:32
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answer #6
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answered by Mariam S 2
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section a million: L=(36x^4-64x^2)/(6c^2+8x) section 2: it fairly is a great distinction of squares. There are surely 2 words and that they are the two squares and the sign indoors the middle is unfavorable. section 3: That divides rather fairly. it would be L=6x^2-8x. section 4 is a similar ingredient, curiously like.
2016-12-14 11:07:17
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answer #7
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answered by Anonymous
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f(x) = 2x^2 + 4x - 6
f(1) = 2(1)^2 + 4(1) - 6
f(1) = 4 + 4 - 6
f(1) = 2 (final answer)
*I don't understand your explaination either.
2007-03-04 21:02:40
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answer #8
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answered by dchosen1_007 2
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f(x) =2x(x+3)-2(x+3)
f(x) = (x+3)(2x-2)
f(x) = 2(x+3)(x-1)
when x= -1, f(-1) =2(-1+3)(-1-1)
Hence f(-1) = (2)*(2)*(-2) = -8
2007-03-04 22:24:28
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answer #9
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answered by bach 2
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Sowwy - You're on your own
2007-03-04 20:52:11
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answer #10
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answered by StingRay 2
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