a 47.0 g golf ball is driven from the tree with an initial speed of 52.0 m/s and rises to a height of 24.6 m. neglecting air resistance, what is it's speed when it is 8.0 m below its highest point?
a. 34.3 m/s
b. 52.0 m/s
c. 69.7 m/s
d. 48.8 m/s
e. 54.9 m/s
2007-03-04 16:16:30 · 2 answers · asked by tico 1 in Science & Mathematics ➔ Physics
At the bottom Energy = 0 + 1/2mvx^2 + 1/2mvy^2 = 0 + 1/2mv^2
= 1/2(0.047)*(52^2)
Energy is conserved so above = mgh + 1/2mv^2
1/2(.047)(52^2) = (.047)(9.8)(16.6) + 1/2(0.047)v^2
Cancel m and solve for v
2007-03-04 16:36:23 · answer #1 · answered by hello 6 · 0⤊ 0⤋
The maximum height tells you the vertical component of the kinetic energy, from which you can determine the horizontal velocity component, which is constant throughout the flight. Then, you simply vector add the vertical velocity resulting from an 8-m fall.
2007-03-05 00:25:29 · answer #2 · answered by arbiter007 6 · 0⤊ 0⤋