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I have the answer for this question from manual but I do now understand on how to get to the solution. Can someone explain ti to me? Thanks.

Q: A mixture weighing 6.2 grams is 28% silicon dioxide or sand, 36% sodium chloride or table salt, and the rest being sodium bicarbonate or baking soda. How many grams of baking soda are present in the sample?

A: 2.852g

2007-03-04 16:10:58 · 5 answers · asked by Anonymous in Science & Mathematics Chemistry

5 answers

Are you sure you have the look at the right answer? 36% of 6.2 g is only 2.232 g not 2.852 g. Either that or you are missing some information. Please double check.

2007-03-04 16:22:42 · answer #1 · answered by ProfPilot 2 · 1 1

28% + 36% = 64%
100% of the material - 64% others = 36% baking soda.
That means the material is 36% NaHCO3.
Multiply 6.2 g by 0.36 to get the grams of NaHCO3.
Hope it healps

2007-03-04 16:26:22 · answer #2 · answered by Anonymous · 0 0

28% + 36% = 64%
100% of the material - 64% others = 36% baking soda.
That means the material is 36% NaHCO3.
Multiply 6.2 g by 0.36 to get the grams of NaHCO3.

2007-03-04 16:17:05 · answer #3 · answered by physandchemteach 7 · 1 1

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2016-11-27 22:18:47 · answer #4 · answered by lacue 4 · 0 0

100% - 28% - 36% = 36%

36% of 6.2 is 2.852.

2007-03-04 16:17:56 · answer #5 · answered by TheOnlyBeldin 7 · 0 1

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