This season, Antonio scored 150% of the number of touchdowns that he scored last season. If he scored 8 touchdowns last season, how many touchdowns did Antonio score this season?
how would u set up this porportion?????
2007-03-04 13:52:34 · 11 answers · asked by jenjen 3 in Education & Reference ➔ Homework Help
this season = 1.5 * last season
this season = 1.5 * 8
this season = 12
2007-03-04 13:54:54 · answer #1 · answered by treseuropean 6 · 0⤊ 1⤋
this season : 150% of 8
150 * (8) /100 = 12 touchdowns or
(150/100) * 8 = 12 touchdowns or
(3/2) * 8 = 12
1 is to 8 as 1 and 1/2 is to 12
2007-03-04 21:58:12 · answer #2 · answered by rooster1981 4 · 0⤊ 0⤋
the answer is 12. 8 is the base, so 100% of 8 is 8. 4 is 50% of 8. 8 plus 4 equals 12.
2007-03-04 21:56:25 · answer #3 · answered by lestermount 7 · 0⤊ 0⤋
The use of "of" in a mathematical sentence means "multiply by"
150% of 8 means 150% x 8
Next, determine what 150% is as a decimal or whole number, like 8, because you need to be comparing apples to apples, not apples to pears.
Then you can figure out what the answer is.
Good luck.
2007-03-04 21:56:50 · answer #4 · answered by Naomi 3 · 0⤊ 0⤋
1.5 times 8 = 12
2007-03-04 21:55:14 · answer #5 · answered by moral TERPitude 2 · 0⤊ 1⤋
ok this is a proportion question
you do
first you convert 150% to 1.5 decimal form
that is now 1.5(8) = touchdowns this season
this equals 12 touchdowns
2007-03-04 21:55:28 · answer #6 · answered by Anonymous · 1⤊ 1⤋
8/x = 1/1.5
cross multiply, so "X" times 1 equals 1 and 8 times 1.5 equals 12.
So "X" equals 12.
2007-03-04 22:00:24 · answer #7 · answered by Eli 2 · 0⤊ 0⤋
You have to take 150% of 8. Remember, in math, of always means multiplication.
Therefore, take 1.50 x 8, which is 12.
2007-03-04 21:55:47 · answer #8 · answered by Anonymous · 0⤊ 1⤋
12 touchdowns
150/100 = x/8
150 x 8 = 100x
1200=100x
12-x
2007-03-04 21:57:04 · answer #9 · answered by jaybird17762001 4 · 0⤊ 0⤋
this season % /100% = this season tds / 8 tds
2007-03-04 21:56:22 · answer #10 · answered by smartass_yankee_tom 4 · 0⤊ 0⤋