By what factor does [OH-] change when the pH increases ...?

Question

by 3?
by 2?
by 1?
by 0.5?

Answer 1

The previous poster almost had it correct:

Remember that pH = -log[H+], and pH + pOH = 14.

So a pH change of 3 means that the [H+] has changed by a factor of 1000, thus the [OH-] has ALSO changed by 1000.

pH change of 2 means 100 fold change of [H+]
pH change of 1 means 10 fold change of [H+]

So far, so good! Here's the mistake:

A change of pH of 0.5 does NOT change the [H+] by a factor of 5! Rather, it changes by a factor of log(5), or 3.16.

Answer 2

Well ... the p part of the pH means -log to the base 10

and so [H+] decreases by 10 fold when the pH goes up by 1

I would expect [OH-] to do the converse - ie. increase by a factor of 10 ... but it might not be exactly the same thing. Maybe some chemistry whiz can help here.

So if pH increases by
3 - the [OH-] should go up by X1000
2 - the [OH-] should go up by X100
1 - the [OH-] should go up by X10
0.5 - the [OH] should go up by X5

Answer 3

p8598dcaecff1aabba86d406b42228d75 +p8598dcaecff1aabba86d406b42228d758598dcaecff1aabba86d406b42228d75=14 this implies that if p8598dcaecff1aabba86d406b42228d75 is going up via 3.6 each and every p8598dcaecff1aabba86d406b42228d75 unit of replace is a ingredient of 10, so 10 X 10 X 10 X 3.98107 So [8598dcaecff1aabba86d406b42228d758598dcaecff1aabba86d406b42228d758598dcaecff1aabba86d406b42228d75] replace via a ingredient of 3981.07 thousand so the p8598dcaecff1aabba86d406b42228d75 would be p8598dcaecff1aabba86d406b42228d75 7 + 3.6 = 10.6

Answer 4

1000
100
10
5