English Deutsch Français Italiano Español Português 繁體中文 Bahasa Indonesia Tiếng Việt ภาษาไทย
All categories

The sum of two consecutive integers is greater than 60. Find the least pair of integers having this property?
do this with let statements too?

2007-03-04 09:29:02 · 5 answers · asked by Tay 1 in Education & Reference Homework Help

5 answers

Let x = the first number
x + 1 = the second number

x + (x + 1) > 60
2x + 1 > 60
2x > 59
x > 29.5

The minimum x is 30, so the minimum pair is 30 and 31

2007-03-04 09:33:00 · answer #1 · answered by bluekitty1541 4 · 0 0

Imagine how to set this for solving... what do you know?

You know the numbers (X and Y) must be consecutive... one right after the other... they are integers... no fractions... You know they must add up to greater than 60. The first integer greater than 60 is 61, so we will let that be our target answer...

so... X + Y = 61 becomes our base equation

but we know Y is just one more than X, so

Y = X + 1

so we can re-write the equation:

X + (X+1) = 61 or, under Distributive Property: X+X+1 = 61

this simplifies to 2X+1 = 61

Do you see how that worked? Can you solve it from here?

2007-03-04 17:42:54 · answer #2 · answered by RNcalledEd 5 · 0 0

30 and 31

2007-03-04 18:05:11 · answer #3 · answered by swimdudensc 2 · 0 0

30 and 31

2007-03-04 17:32:23 · answer #4 · answered by Anonymous · 0 0

30 and 31. to make this easy first divide 60 by 2 so u get 30 and 30. next since they have to be intigers, first try 29 and 30 since u already know one answer is thirty. since thats 59, try 30 and 31. that gives u 61 and the answer.

2007-03-04 17:37:59 · answer #5 · answered by Anonymous · 0 0

fedest.com, questions and answers