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If Mars is 1.67 AU (Astronomical Units) from the SUn and Jupiter is 5.47 AU from thr Sun, hoe many days would it take a spacecraft traveling at 45,000 kilometers/hour to travel from Mars to Jupiter?

2007-03-04 09:27:33 · 1 answers · asked by Anonymous in Science & Mathematics Astronomy & Space

1 answers

There really is not enough information to narrow the answer down to a single answer.

If what you want to know is how long it takes to travel 5.47-1.67=3.8 AU at 45,000 kilometers per hour then you need to know how long an AU is. I remember it in miles as 93,000,000 miles. That is about 150,000,000 kilometers.
Divide the distance by the speed and you get an answer.
150000/45=3300 hours(approximate due to limited reliability of distance)

Speed is relative. That means you need to have something that is thought of as standing still and something that is moving relative to that thing. The speed specified in this problem is not specified to be relative to anything in particular. Jupiter and Mars are moving at different speeds.

The distances from the Sun of the two planets Jupiter and Mars usually are measured in different directions from the Sun. The maximum distance between Jupiter and Mars would be the sum of their distances from the Sun when they are on opposite sides of the Sun. That would mean that they are 7.14 AU apart. That is almost twice the minimum distance.

The most energy efficient method of traveling from Mars to Jupiter is not to maintain a constant speed. It would at least require traveling half way around the sun on an ellipse that parallels the orbit of each planet. A really efficient method probably would require several passes around the sun using the planets nearer the sun to accelerate the spacecraft to reach the outer planets. The Voyager series of spacecraft used this technique to travel to the outer plants.

2007-03-04 14:25:52 · answer #1 · answered by anonimous 6 · 0 0

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