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2007-03-04 09:03:05 · 2 answers · asked by timotheusametheus 1 in Science & Mathematics Physics

Source: A Short History of Nearly Everything
Author: Bill Bryson

2007-03-04 10:08:53 · update #1

2 answers

Divide the mass of the Cathedral by the volume of the pea.

HTH ☺

Doug

2007-03-04 09:09:35 · answer #1 · answered by doug_donaghue 7 · 0 0

Where do you get your information? Sounds slightly bogus to me. Even an atom the size of a pea would be mostly empty space because the pea size diameter would be the diameter of the biggest electron orbital. That leaves only a small portion of nucleus to add any weight. Hardly enough to match the weight of a Catherdral.

2007-03-04 17:16:37 · answer #2 · answered by SteveA8 6 · 0 0

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