could someone please explain to me how to solve this? thanks
Consider the reaction 4PH3 ----> P4 + 6H2
If in a certain experiment over a specific time period, 0.0048 mol PH3 is consumed in a 2.0L container each second of reaction, what are the rates of production of P4 and H2 in this experiment?
2007-03-04 06:51:04 · 2 answers · asked by sandcastlesinair 1 in Science & Mathematics ➔ Chemistry
It will follow the stoichiometry. The amount of PH3 that is reacting is 0.0024 M/s. You will produce 0.0006 M/s P4 and 0.0036 M/s H2.
The general rule is, for a reaction aA + bB ---> cC + dD, the relationship between reaction rates is:
-1/a (delta [A]/delta t) = -1/b (delta [B]/delta t) = 1/c (delta [C]/delta t) = 1/d (delta [D]/delta t)
2007-03-04 06:58:00 · answer #1 · answered by TheOnlyBeldin 7 · 0⤊ 0⤋
quick reaction
2007-03-04 06:58:46 · answer #2 · answered by Anonymous · 0⤊ 0⤋