Math help please?

Question

Factor completely. 12(x + 1)^2 - 17(x + 1) + 6

Answer 1

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Problem: Factor completely, 12(x + 1)^2 - 17(x + 1) + 6


Solution:

Square (x + 1) and distribute - 17(x + 1):
12(x^2 + 2x + 1) - 17x - 17 + 6

Distribute 12(x^2 + 2x + 1):
= 12x^2 + 24x + 12 -17x -17 + 6

Combine like terms:
= 12x^2 + 7x + 1 < ~~ This can still be factored:
= (3x + 1)(4x + 1) < ~~ Answer ♪♫♪♫
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Answer 2

First do the squaring:

12(x^2 + 2x + 1) - 17(x + 1) + 6

Then multply through the parentheses:

12x^2 + 24x + 12 - 17x - 17 + 6

Finally, combine like terms:

12x^2 + 7x + 1

Answer 3

start from 12X^2+7X+1

Answer 4

12(x+1)^2-17(x+1)+6
12(x^2+2x+1)-17x-17+6
12x^2+24x+12-17x-11
12x^2+7x+1
(3x+1)(4x+1)

Answer 5

12x^2+7x+1

here you go!