easy chem question help?!?

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easy chem question help?!?

four (4.0) liters of helium gas have a pressure of 800.0 torr. what will be the new pressure if the volume is reduced to 1.0 liter. (n and t constant) . ?

2007-03-04 01:54:43 · 3 answers · asked by ? 1 in Science & Mathematics ➔ Chemistry

3 answers

nRT=P1V1
nRT=P2V2
therefore P1V1=P2V2
V1=4 L, P1=800 torr
V2=1L, P2?
we want to find P2
800*4=P2*1
P2=800*4=3200 torr
if you want to change to atm. 3200torr*1atm/760torr=4.21 atm

2007-03-04 02:23:28 · answer #1 · answered by Helper 6 · 0⤊ 0⤋

Use the Boyle's Law formula

P1V1 = P2V2

You have all of the data. Just plug in and solve for P2

2007-03-04 10:15:00 · answer #2 · answered by reb1240 7 · 0⤊ 0⤋

I just answered your 1st question. When I see this second question, I know you just don't use your brain.

2007-03-04 10:00:44 · answer #3 · answered by sammy 2 · 0⤊ 1⤋