The inside wall and base are to be painted.
What is the area to be painted?
Cheers! =]
2007-03-04 01:28:33 · 10 answers · asked by Anonymous in Science & Mathematics ➔ Mathematics
Inside wall area
= (pi x diameter) x depth
= (pi x 120) x 20
= 7539.8 cm2
Base area
= pi x radius^2
= pi x (60^2)
= 11309.7 cm2
Total area
= 7539.8 + 11309.7
= 18849.5 cm2
2007-03-04 02:15:31 · answer #1 · answered by Kemmy 6 · 0⤊ 0⤋
Area of inside wall = pi*dia*depth = pi*120*20
=2400pi cm^2
Base area = pi*r^2 = pi*60^2
=3600pi cm^2
Total Area = 6000pi cm^2 = 18849.56 cm^2
2007-03-04 01:37:50 · answer #2 · answered by Anonymous · 0⤊ 0⤋
area of base= pi*r^2
=pi* (60)^2
=11309.7cm^2
Area of inside wall = 2*pi*rh
= 2*pi* 60* 20
= 7539.8
Total Area to be painted=18849.5cm^2= 18850cm^2
2007-03-04 01:36:02 · answer #3 · answered by Maths Rocks 4 · 0⤊ 0⤋
Surface area would be depth x pi x D
20 x 3.14 x 120 square centimeters
2007-03-04 01:34:56 · answer #4 · answered by R.E.M.E. 5 · 0⤊ 0⤋
circumference=2x pi x r = 2pi( 120/2 ) = 376.9cm
area to be painted = circumference x depth =376.9 x 20 =7540cm^2
2007-03-04 01:34:03 · answer #5 · answered by llcold 2 · 0⤊ 0⤋
Area is (pi)x (dia/2)^2 + depth x (pi) x dia
2007-03-04 01:39:58 · answer #6 · answered by physicist 4 · 0⤊ 0⤋
circ = dia X 3.142
= 1.20 x 3.142 = 3.77 x 0.2 = 0.75 sq mtrs ( wall )
area = 3.142 x rad sqrd
=0.6x0.6= 0.36 x3.142 = 1.13sq mtrs ( base )
total area = 0.75 + 1.13 =1.88sq mtrs
2007-03-04 01:53:24 · answer #7 · answered by Dry fly. 1 · 0⤊ 0⤋
area to be painted=pie*(60)^2+2*pie*60(60+20)
=pie[3600+2*4800]
=pie*13200 cm^2
2007-03-04 01:35:47 · answer #8 · answered by SS 2 · 0⤊ 0⤋
...Total area = (π x D x h) + (π x r²)
... = (3.142 x 120 x 20) + (3.142 x 60 x 60)
... = 7,540.8 + 11, 311.2 = 18,852 cm²
... = 1.885 m²
2007-03-04 03:31:38 · answer #9 · answered by Norrie 7 · 0⤊ 0⤋
two x pi x r
2007-03-04 01:35:26 · answer #10 · answered by Emilee 5 · 0⤊ 1⤋