Reduce (x^2 - 4x - 12)/(x^2 +5x + 6).
2007-03-04 01:17:25 · 6 answers · asked by steph158_4 1 in Science & Mathematics ➔ Mathematics
x² - 4x - 12 / x² + 5x + 6 =
(x + 2)(x - 6) / (x + 2)(x + 3) =
(x - 6) / (x + 3)
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2007-03-04 02:24:06 · answer #1 · answered by SAMUEL D 7 · 0⤊ 0⤋
(x^2 - 4x - 12)/(x^2 +5x + 6).= (x + 2)(x - 6)/(x + 3)(x + 2) = (x - 6)/(x + 3)
2007-03-04 09:25:12 · answer #2 · answered by physicist 4 · 0⤊ 0⤋
(x - 2)/(x - 3)
2007-03-04 09:25:29 · answer #3 · answered by melissa a 1 · 0⤊ 1⤋
=[(x-6)(x+2)]/[(x+3)(x+2)]
cancel out (x+2)
=(x-6)/(x+3)
2007-03-04 10:06:10 · answer #4 · answered by violettorose 3 · 0⤊ 0⤋
[x^2-6x+2x-12]/[x^2+3x+2x+6]
=(x-6)(x+2)/(x+3)(x+2)
=(x-6)/(x+3)
2007-03-04 09:25:12 · answer #5 · answered by Maths Rocks 4 · 0⤊ 0⤋
=(x^2-6x+2x-12)/(x^2+3x+2x+6)
=[x(x-6)+2(x-6)]/[x(x+3)+2(x+3)]
=(x+2)(x+6)/(x+2)(x+3)
=x-6/x+3
2007-03-04 09:28:12 · answer #6 · answered by SS 2 · 0⤊ 0⤋