(x^2 + x - 6)/(x + 3)
2007-03-04 01:07:55 · 7 answers · asked by markbernetie 1 in Science & Mathematics ➔ Mathematics
(x² + x - 6)) / (x + 3) =
x² + x - 6 =
((x - 3) (x - 2)
- - - - - - -
(x + 3)(x - 2) / (x + 3). . . .x + 3 cancell
x - 2
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2007-03-04 02:38:13 · answer #1 · answered by SAMUEL D 7 · 0⤊ 0⤋
x^2 + x -6 = (x -2)(x +3)
Thus (x^2 + x - 6)/(x + 3) = (x -2)(x +3)/(x + 3) = (x -2)
2007-03-04 01:18:25 · answer #2 · answered by physicist 4 · 0⤊ 0⤋
x^2 +x -6 has two roots -3 and 2
so you can write it (x-2)(x+3)
and if you divide (x-2) (x+3) /(x+3)
you obtain x-2
2007-03-04 01:15:18 · answer #3 · answered by maussy 7 · 0⤊ 0⤋
=(x+3)(x-2)/(x+3)
=x-2 (with x different than -3)
2007-03-04 01:15:50 · answer #4 · answered by abd 5 · 0⤊ 0⤋
Yeah because when you factor the first nomial or whatever you're going to get (x+3)(x-2)/(x+3), and then you can just cross both (x+3)s out and you're left with (x-2) as your answer.
2007-03-04 01:13:00 · answer #5 · answered by Anonymous · 0⤊ 0⤋
x^2+x-6= x^2+3x-2x-6=X(x+3)-2(x+3)=(x-2)(x+3)
therefore (x-2)(x+3)/(x+3)= x-2
2007-03-04 01:33:18 · answer #6 · answered by somu 1 · 0⤊ 0⤋
=[(x+3)(x-2)]/(x+3)
cancel out (x+3)
=(x-2)
2007-03-04 02:08:24 · answer #7 · answered by violettorose 3 · 0⤊ 0⤋