Can you calculate the mass of aluminium oxide, Al2O3, needed to produce 1,0 tonnes of aluminium?
(1.0 tonne= 1.0 x 10^6g)
2007-03-04 00:35:12 · 4 answers · asked by Anonymous in Science & Mathematics ➔ Chemistry
Assuming that all of the Al2O3 is reduced to Aluminum metal, then the product is just the ratio of the Gram Atoms of Al in Al2O3.
AGM Al = 26.98 g/mol * 2 = 53.96 g/mol
FM Al2O3 = 101.96 g/mol
53.96 / 101.96 = 0.5292 or 52.92% Al
1.0 tonne / 0.5292 = 1.8896 tonne of Al2O3
[you may want to round it to 1.89 tonne]
The actual process (electrolysis) is:
2 Al2O3 + 3 C (s) --> 2 Al (s) + 3 CO2 (g)
2007-03-04 05:02:29 · answer #1 · answered by Richard 7 · 11⤊ 0⤋
Al2O3 --> 2Al + 3/2O2
amt. of aluminium=1.0 x 10^6 / 27.0=37040
amt. of Al2O3 req'd=37040/2=18520
mass of Al2O3 req'd=18520 x(27.0 x 2 + 16.0x3) = 18520 x 102.0=1890000g=1.89 tonnes
2007-03-04 08:41:26 · answer #2 · answered by llcold 2 · 0⤊ 0⤋
I must be really bad then, I dont have a clue...I can live with that though..
2007-03-04 08:39:58 · answer #3 · answered by ? 7 · 0⤊ 0⤋
WHAT?!!!!!!!!!!!!!!!!!!!!!!
2007-03-05 10:56:14 · answer #4 · answered by lotsofadventures04 2 · 1⤊ 0⤋