2007-03-04 00:10:46 · 13 answers · asked by tony t 1 in Science & Mathematics ➔ Mathematics
We can write the consecutive odd numbers as 2n +1, 2n +3 and 2n +5, where n is an integer. Then we have that
87 = (2n +1) + (2n +3) +(2n +5)
= 6n + 9,
ie. n = 13.
Thus our three consecutive odd numbers are 27, 29 and 31.
2007-03-04 00:18:00 · answer #1 · answered by MHW 5 · 0⤊ 0⤋
Let the three odd numbers be x, x+2, x+4
so their sum is 87
therefore, x+x+2+x+4=87
3x+6=87
3x = 81
x= 81/3
= 27
so the first number is 27
x+2 ==> 29
x+4 ==> 31
therfore 27 + 29+ 31 = 87
2007-03-04 08:46:12 · answer #2 · answered by Drools over home made food 6 · 0⤊ 0⤋
let (2n +1 ) be the first odd number. Then the folowing odd numbers are
2n+3 and 2n+5
Thus (2n + 1) +(2n +3) + (2n + 5) = 87 ==> 6n + 9 = 87
==> n = 13 Thus the first odd number is 2x13 +1 = 27
and the others are 29 and 31 .We have 27 + 29 + 31 = 87
2007-03-04 08:23:03 · answer #3 · answered by physicist 4 · 0⤊ 0⤋
27,29,31.
If you divide 87 by 3, you get 29. So the odd number before and after that will add up to the same as 29+29. So you have your answer.
2007-03-04 08:15:12 · answer #4 · answered by Anonymous · 0⤊ 0⤋
X + X + 2 +X + 4=87
3X + 6 = 87
3X = 81
X = 27
X+2 = 29
X+4 = 31
2007-03-04 08:21:00 · answer #5 · answered by ©2009 7 · 0⤊ 0⤋
3 47 37
2007-03-04 08:38:18 · answer #6 · answered by cobra sly 1 · 0⤊ 0⤋
let the three numbers are 2n-3,2n-1,2n+1..
their sum= 6n-3= 3( 2n-1) = 87
dividing by 3,
2n-1 = 29, n=30/2= 15
therrfore the nos. are
2(15)-3, 2(15)-1,2(15)+1 i.e 27,29,31
2007-03-04 08:24:24 · answer #7 · answered by Knightmare 1 · 0⤊ 0⤋
n + (n + 2) + (n + 4) = 87
3n + 6 = 87
n = 81/3 = 27
The numbers are 27, 29, 31
2007-03-04 08:15:43 · answer #8 · answered by Thomas K 6 · 0⤊ 0⤋
27, 29, 31
2007-03-04 08:16:40 · answer #9 · answered by juankapunk 1 · 0⤊ 0⤋
do your own homework... dont have other people do it for you!
2007-03-04 08:15:40 · answer #10 · answered by picklegirl326 3 · 0⤊ 0⤋