2007-03-03 20:57:03 · 19 answers · asked by 123 3 1 in Science & Mathematics ➔ Mathematics
Of course , Yes.
2007-03-05 22:20:10 · answer #1 · answered by ankit a 1 · 0⤊ 0⤋
Ofcourse,
(33+333-33-33+33-33)/3=100
ie.300/3=100
2007-03-03 21:09:41 · answer #2 · answered by ? 2 · 1⤊ 0⤋
Yes , it is possible .
3 thirteen times .
(3 * 3 + 3 + 3 + 3 + 3 + 3 + 3 + 3 + 3) * 3 )+ (3 / 3) = 100
2007-03-03 23:57:47 · answer #3 · answered by Anonymous · 0⤊ 1⤋
3*3*3*3 +3+3+3+3+3+3+3^(3-3) = 100
2007-03-03 22:47:51 · answer #4 · answered by ganesan 2 · 0⤊ 0⤋
Try
100 = 3^(3 +3/3) +(3+3+3) + 3x3 +33/33
2007-03-03 21:20:48 · answer #5 · answered by physicist 4 · 3⤊ 0⤋
Its simple.
3 * 3 * 3 * 3 + (3+3+3+3+3+3) + 3 ^ (3 - 3) = 100.
2007-03-03 22:27:28 · answer #6 · answered by TG 2 · 0⤊ 0⤋
There will be many, many possible ways of answering this:
here is another:
333 - 333 + 333/3 - 33/3 = 333 - 333 + 111 - 11 = 100
2007-03-03 21:32:58 · answer #7 · answered by sumzrfun 3 · 0⤊ 1⤋
Yes, it is possible.
This is how it is possible:
((3 * 3 + 3 + 3 + 3 + 3 + 3 + 3 + 3 + 3) * 3 )+ (3 / 3) = 100
2007-03-03 21:17:58 · answer #8 · answered by ? 6 · 5⤊ 0⤋
Yes, it is possible.
This is how it is possible:
((3 * 3 + 3 + 3 + 3 + 3 + 3 + 3 + 3 + 3) * 3 )+ (3 / 3) = 100
2007-03-03 23:27:03 · answer #9 · answered by kritya s 1 · 1⤊ 2⤋
Yes
2007-03-03 21:04:33 · answer #10 · answered by Anonymous · 0⤊ 0⤋
one more:
(333*3 -33*3-33 +33)/(3*3)
= (999-99)/9
=100
2007-03-04 01:25:06 · answer #11 · answered by Smart Indian 4 · 1⤊ 0⤋