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Multiply, using the vertical method. (m + 3n)(m^2 - 3mn + 9n^2)

2007-03-03 19:53:08 · 2 answers · asked by Anonymous in Science & Mathematics Mathematics

2 answers

Simply Multiply m by the secnd pranteses , then Multiply 3n to the second pranteses then add these two :

(m+3n)(m^2-3mn+9n^2) =
m^3+3m^2n+9m.n^2+3n.m^2-9m.n^2+18n^3 =
m^3+3m^2.n+3n.m^2+18n^3

2007-03-03 21:23:08 · answer #1 · answered by Kiamehr 3 · 0 0

m^2+9n^2m+3nm^2-m

That's my guess but I'm not totally sure.
Sorry!

2007-03-04 04:12:09 · answer #2 · answered by ? 6 · 0 0

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