5x + 5y = 0,
y = –3x – 2
2007-03-03 19:32:12 · 7 answers · asked by John Crow 1 in Science & Mathematics ➔ Mathematics
5x + 5y = 0,
=> 5x = -5y => x= -y
y = –3x – 2
=> y = -3(-y) - 2 => y = 3y - 2 => 2y=2=>y=1 and x=-1
2007-03-03 19:39:52 · answer #1 · answered by Zulu 2 · 0⤊ 0⤋
5x+5(-3x-2)=0
5x-15x-10=0
-10x - 10 = 0
-10x =10
-x=10/10
-x=1
x=-1
so now y=-3x - 2
so substitute x in the y equation and u will get
y=-3(-1) - 2
y=3-2
y=1
so to check now substitute x and y in the main equation
5x +5y=0
=5(-1) + 5(1)
=-5+5
=0
so now x=-1 and y=1
2007-03-04 03:54:13 · answer #2 · answered by Anonymous · 0⤊ 0⤋
5x + 5 y = 0, so x + y = 0 and y = - x
Substituting this in second equation, we have
y = - 3x -2 or - x = -3x -2 and 2x = -2,
x = -1, y = -x = 1
2007-03-04 03:52:17 · answer #3 · answered by Swamy 7 · 0⤊ 0⤋
5x + 5(-3x - 2) = 0
5x - 15x - 10 = 0
-10x - 10 = 0
-10x = 10
x = -1
2007-03-04 03:40:38 · answer #4 · answered by wildcat_gurl_2008 2 · 0⤊ 0⤋
by substitution
5x + 5(-3x-2) = 0
5x - 15x - 10 = 0
-10x = 10
x = -1
so y = -5x/5 = -(-5)/5 = 1
2007-03-04 03:47:45 · answer #5 · answered by Vinod 2 · 0⤊ 0⤋
substitute y for x.
5x+5(-3x-2)=0
5x-15x-10=0
-10x=10
x=-1
sub in to find y.
y=-3(-1)-2
y=1
2007-03-04 03:55:59 · answer #6 · answered by Paul Wall 2 · 0⤊ 0⤋
5(x+y)=0
x+y=0
x+(-3x-2)=0
x-3x-2=0
-2x-2=0
-2x=2
x= -1
y= 1
2007-03-04 03:51:40 · answer #7 · answered by reza 2 · 0⤊ 0⤋