Help please
2007-03-03 19:31:02 · 6 answers · asked by jdog 3 in Science & Mathematics ➔ Mathematics
2 divided by the 6th root of 8
2007-03-03 19:43:31 · update #1
2 divided by the 6th root of 8
=2/[(2)^3}^1/6
=2/2^1/2
=2*2^-1/2
=2^(1-1/2)
=2^1/2
=sqrt 2
2007-03-03 23:22:24 · answer #1 · answered by alpha 7 · 0⤊ 0⤋
2
2007-03-03 19:36:07 · answer #2 · answered by kumar_subodh1984 2 · 0⤊ 0⤋
sooo 2 / 8^(1/6).....if thats your question..just plug that into your calculator.
Anyways. Roots are the same as taking a number to the power of
1 divided by your number
So. 3rd root of 8 is 8^(1/3) 4th root is 8 ^(1/4)
2007-03-03 19:51:27 · answer #3 · answered by My name is not bruce 7 · 0⤊ 0⤋
6th root of 8 is 8 power 1/6
8 = 2 to the power 3
so 8 ^ 1/6 = (2^3)^1/6 = 2^(3/6) = 2^(1/2)
2 divided by 2^(1/2) is 2^(1 - (1/2)) = 2^(1/2) = approx. 1.414
2007-03-03 19:51:30 · answer #4 · answered by Vinod 2 · 0⤊ 0⤋
You mean 8 to the 2/6th power?
As in, 8 to th 1/3 power?
As in, the cube root of 8?
As in, the cube root of 2 cubed?
As in, 2?
:)
2007-03-03 19:35:50 · answer #5 · answered by Anonymous · 0⤊ 0⤋
just use calculator the answer is
0.7598356856513
2007-03-03 19:53:32 · answer #6 · answered by Ali 5000 5 · 0⤊ 1⤋