Yeah I know the 22/7 but I want to know the formula that they have plugged into the supercomputers that have been running for years and pumped out numbers in the billions, trillions, quadrillions, etc...
2007-03-03 17:31:10 · 7 answers · asked by djsurreal3 1 in Science & Mathematics ➔ Mathematics
There are many, many different algorithms used for computing pi.
2007-03-03 17:35:30 · answer #1 · answered by bruinfan 7 · 0⤊ 0⤋
22/7 is a very rough approximation at which most mathematicians would cringe.
The proper way to solve for pi is in terms of an infinite series, and using calculus to determine which value the series converges to. Unfortunately, it converges too slowly to be of much use by hand, but with a computer's speed it's becoming possible to calculate it further.
The series is in terms of fibonacci numbers.
It's at the very bottom of this page: http://www.geom.uiuc.edu/~huberty/math5337/groupe/expresspi.html
I must add that there is still no PERFECT way to actually calculate pi yet. It is just the ratio circumference/diameter
2007-03-03 17:43:23 · answer #2 · answered by jsprplc2006 4 · 0⤊ 0⤋
Reactance is the importance of the impedance that makes up the "imaginary" area. This imaginary area is truly no longer imaginary in any respect, we merely call it that to tell apart it from the "genuine" area. the present which flows because of the real area bypass "in section" with the utilising source. the present which flows because of the "reactive" area of the impedance, flows with both a lead or lag relative to the utilising source. usually, Z(f) = R + j X(f), the position X(f) represents the reactance as a function of frequency. The "j" which precedes the reactive area, represents a time relationship, it truly is not on time (-j) or stepped ahead (+j) via ninety ranges. Now, i visit derive the expression for reactance of cap. C = Q / V it really is the needed definition of capacitance. CV = Q, Now taking the first time by-product of each part: C*(dV/dt) = dQ/dt = i, considering dQ/dt is merely the present. For resistance, R = V_dc/I_dc For reactance, X = importance(V_ac) / importance(I_ac) enable V_ac = sin(2pi f)t, then dV/dt = (2pi f) cos(2pi f)t the present i = C dV/dt = C (2pi f) cos(2pi f)t This tells us if the voltage on the capacitor is a sinewave with amplitude of one million volt, then the present via the capacitor will be a cosine wave with an amplitude it truly is determined via 2*pi*f*C, or the reactance is a million/(2*pi*f*C). the very truth the present is a cosine wave even as the voltage is a sine wave tells us that the present in a capacitor leads the voltage for the period of it via ninety ranges.
2016-11-27 20:13:06 · answer #3 · answered by mcraney 4 · 0⤊ 0⤋
I'm not sure on the exact formula but I know they can use the one by Archimedes or James Gregory.
2007-03-03 17:35:43 · answer #4 · answered by CyberKnight 2 · 0⤊ 0⤋
the only difference is that they have more floating points places. if you want to know more about some elegant work on solving for Pi check out
http://www.mcs.surrey.ac.uk/Personal/R.Knott/Fibonacci/fibpi.html
2007-03-03 17:43:36 · answer #5 · answered by gbryant1 1 · 0⤊ 0⤋
Check this out it should give you the details that you want!
http://en.wikipedia.org/wiki/Pi
2007-03-03 17:38:34 · answer #6 · answered by Cromag 3 · 0⤊ 0⤋
it's not a formula. it's just the ratio of the circumference to the diameter.
2007-03-03 17:36:59 · answer #7 · answered by badegg_11sg 2 · 1⤊ 1⤋